q^2+3q-54=(q-6)(q+)

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Solution for q^2+3q-54=(q-6)(q+) equation: 



q^2+3q-54=(q-6)(q+)

We move all terms to the left:

q^2+3q-54-((q-6)(q+))=0

We add all the numbers together, and all the variables

q^2+3q-((q-6)(+q))-54=0

We multiply parentheses ..

q^2-((+q^2-6q))+3q-54=0



We calculate terms in parentheses: -((+q^2-6q)), so:

(+q^2-6q)

We get rid of parentheses

q^2-6q

Back to the equation:

-(q^2-6q)



We add all the numbers together, and all the variables

q^2+3q-(q^2-6q)-54=0

We get rid of parentheses

q^2-q^2+3q+6q-54=0

We add all the numbers together, and all the variables

9q-54=0

We move all terms containing q to the left, all other terms to the right

9q=54

q=54/9

q=6

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